Safety is very important when designing and/or building a device powered by potentially lethal electrical sources such as residential AC line power. Explain how you can prove that the metal case of your power supply is indeed “grounded” for safety, such that an internal fault from one of the “hot” conductors to the metal case will result in a short-circuit that will trip the power receptacle’s fuse or breaker rather than shock the individual touching the case?
Hint: a visual inspection is not good enough, and we don’t want to actually create a ground fault situation to test the grounding.
Measure resistance from the ground prong on the power plug to the metal case. The resistance should be no more than a few tenths of an ohm. A resistance measurement of 0.5 ohm or more indicates a poor connection.
As a general policy, I inspect each and every one of my students’ power supplies before energizing for the first time. This does not mean, though, that I am the one making the meter measurements! Each student must prove to me that their grounding is adequate by making the meter measurement under my direct supervision. This way, they learn how to do it themselves while safety is still personally ensured by me.
I also have the students tug on the wire connections while making this test, to ensure that it is not a random low-resistance measurement we are seeing with the ohmmeter. Loose wire connections are best tested by resistance measurements under mechanical stress, not by visual inspection alone.
When connecting components together to build your power supply, it is important that you use the proper type(s) of wire. Identify what characteristics are required for the wires you use in this project, for each of the following parameters:
For the first two parameters, identify the values of expected current and voltage to be encountered in your power supply circuit, for both the AC and the DC sections.
Why do you suppose stranded wire might be preferred for a project such as this? I’ll give you a hint: it is not for any electrical property of the wire as much as it is for mechanical considerations.
Ampacity figures may not be readily available for wires of the gauge most electronics students are accustomed to dealing with. However, ampacity for small-gauge wire may be roughly calculated by plotting data points of published wire ampacities for wire of several larger gauges, and then extrapolating downward on the gauge scale. If nothing else, this would be a great example to students of how to use simple statistical techniques (regression, curve fitting, plotting) to make practical estimations.
How do we tell which winding of the step-down power transformer is the primary, and which is the secondary, without actually powering it up with AC line power? This is often an issue when students purchase cheap transformers that are unmarked and undocumented.
Use an ohmmeter to measure the resistance of each winding. The primary winding of a step-down transformer will contain a longer length of wire, of smaller cross-sectional area, than the secondary winding. With these two factors, the resistance difference between windings should be obvious.
Care should be taken if the transformer in question is a complete unknown. It may be impossible to tell what the respective voltage ratings of the windings are if one does not even know whether the transformer was designed for line power (120 volts, 60 Hz AC in the United States) or not. Small power transformers are easy enough to obtain from electronics parts suppliers and from scrap consumer electronic devices (stereos, computer accessories, etc.) that no one should have to take chances with a completely unknown transformer.
When you measure the low-voltage AC output of your transformer and compare that measurement to the rectified and filtered DC output voltage, you will notice something very counter-intuitive. The DC output voltage reading is substantially greater than the unrectified AC voltage from the transformer’s secondary winding!
Explain why this is, and then show mathematical calculations that relate the two voltage measurements together with reasonable accuracy.
This is something that catches almost all students by surprise when they first measure the voltages. I’ll give you a big hint why the rectified and filtered (DC) output voltage is so much greater than the unrectified (AC) secondary voltage: the AC voltage measurement you make with your voltmeter is most likely an RMS measurement, not a peak measurement.
Let students figure out this mystery on their own: it is one of those phenomena that really reveals the nature of RMS measurements in contrast to peak measurements.
One thing you will want to do with your completed power supply is subject it to a full-current (1 amp) load, and test the output voltage. To do this, you will need a load that draws close to 1 amp without overheating or causing other problems.
A resistor will work fine for this task, but which resistor should you use? Identify the two parameters you must be concerned about when selecting a load resistor for the task, and explain exactly how those parameters will be calculated.
The two parameters are: resistance (how many ohms), and power rating (how many watts). I will leave it to you to show how to calculate each parameter for your particular power supply.
Even though this is nothing more than an application of Ohm’s Law, do not be surprised if students approach you dumbfounded by this question. There is a large cognitive difference between calculating current and power for a resistor of known value and a voltage source of known voltage, and selecting a resistor based on known current and voltage for a practical test of a power supply. While studying Ohm’s Law in a theoretical context, students become comfortable making calculations on paper, but may not realize just how to apply that same math to a real-world situation. Or, they may express apprehension when faced with having to make calculations that carry real consequences (such as damaging their power supply!).
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