AC Electric Circuits
Mutual Inductance
12 questions By Tony R. Kuphaldt
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Question 4 of 12
Write the equation describing the voltage induced in this coil, solving for (instantaneous) induced voltage (e) in terms of the instantaneous magnetic flux (φ) and the number of turns of wire in the coil:

Reveal answere = N\(\frac{dφ}{dt}\)
Follow-up question: algebraically manipulate this equation to solve for the number of turns (N) given all the other quantities.
Notes:It should be noted that in this particular case, N is equal to three (counting the turns in the illustrated coil).
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Question 5 of 12
There are two wire windings wrapped around a common iron bar in this illustration, such that whatever magnetic flux may be produced by one winding is fully shared by the other winding:

Write two equations describing the induced voltage at each winding (ep = ... and es = ...), in each case expressing the induced voltage in terms of the instantaneous magnetic flux (φ) and the number of turns of wire in that winding (Np and Ns, respectively).
Then, combine these two equations, based on the fact that the magnetic flux is equal for each winding.
Reveal answerep = Np dφ dtes = Ns dφ dtThen, combining the two equations:
ep Np= es NsNotes:Obtaining the last equation is an application of the mathematical truth that quantities equal to the same thing are equal to each other (if a = c and b = c, then a = b).
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Question 6 of 12
There are two wire windings wrapped around a common iron bar in this illustration, such that whatever magnetic flux may be produced by one winding is fully shared by the other winding:

Write two equations describing the induced voltage at each winding (ep = ... and es = ...), in each case expressing the induced voltage in terms of the instantaneous current through that winding (ip and is, respectively) and the inductance of each winding (Lp and Ls, respectively).
We know that the induced voltages in the two windings are related to each other by this equation, if there is perfect “coupling” of magnetic flux between the two windings:
ep Np= es NsKnowing this, write two more equations describing induced voltage, this time expressing the induced voltage in each winding in terms of the instantaneous current in the other winding. In other words,
ep = ... is es = ... ip Reveal answerEquations describing self-inductance:
ep = Lp dip dtes = Ls dis dtEquations describing inductance from one winding to the other:
ep = Ls Np Nsdis dtes = Lp Ns Npdip dtNotes:The first two equations are mere review. The second two equations require algebraic manipulation and substitution between equations.


