Identify some different ways you can create the sine-wave audio tracks necessary to turn the media player into a signal generator.
Some computer programs will generate “wave” files (.wav) according to the wave-shape, amplitude, and frequency specified. Using a program such as this is one of the best ways to obtain the necessary audio tracks.
There are other ways to obtain good audio tracks, including recording the output of another signal generator. I have had such good success with the computer method, though, I can’t imagine that recording an analog source - no matter how good that source may be - would do much better.
Incidentally, the program I use is a Linux application called sox. It is a general-purpose sound file converter utility that also happens to have a “synthesizer” mode where it can generate audio tracks. Using this utility, I created twenty sine-wave tracks and then burnt them to a CD-R, where I could then play the tracks using a cheap ($17.00, 2004 U.S. currency) CD-audio player. I found the best wave quality to be when the player’s “anti-skip” mode was turned off.
No ground symbols are seen anywhere in the schematic diagram, yet there are “ V” and “-V” labels for the two poles of the DC power supply. Where is ground in this circuit, and what establishes its potential?
What purpose does the 1N4001 diode serve in this circuit?
The diode serves to establish a small bias voltage between the two transistors’ bases, to minimize the amount of crossover distortion.
Theoretically, the op-amp should be able to handle the “handoff” between the two transistors even with no bias voltage, but since no op-amp has an infinite slew rate, there will be some crossover distortion under load (such as when driving am 8 Ω speaker). Placing a bit of DC bias voltage between the two transistor bases helps push them closer to ideal class-B operation, giving the op-amp an easier time of managing the crossover periods.
It may be important to decouple the power supply rails in this amplifier circuit, just as it is important to decouple the power supply rails in a variety of circuits where fast [dv/dt] rates can exist, and/or when electrical noise is problematic. Explain what “decoupling” is, and what it does.
To “decouple” the power supply means to place capacitors between the power supply rails to stabilize the DC voltage, shorting out AC noise and transient voltage spikes from interfering with the normal operation of the circuit.
Follow-up question: where do you think decoupling capacitors would be the most effective, located back at the power supply, or close to the power terminals of the operational amplifier and power transistors? Explain your reasoning.
I have seen the addition of decoupling capacitors turn a useless circuit into a flawless performer. In the case of an audio amplifier, DC power supply rails that are not properly decoupled may serve as feedback paths for unwanted signals, causing oscillations. These oscillations, if unchecked, may even damage the circuit!
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