The most common application of the op-amp is as the *error amplifier* of a negative-feedback circuit. Nowadays, op-amps come in two types: the *voltage-feedback amplifier* (VFA), for which the input error is a *voltage*; and the *current-feedback amplifier* (CFA), for which the input error is a *current*.

VFAs have gained widespread popularity since they became available in monolithic form in the 1960s. CFAs, on the other hand, became available in monolithic form only in the 1980s, when many potential users, by then well versed with the VFA, did not feel at total ease with the newer CFA.

The purpose of this article is to dispel possible misunderstandings of these two device types by pointing out their similarities as well as their differences.

### VFA and CFA Basics

#### Example VFA: Voltage-Controlled Voltage Source

With reference to Figure 1*a*, the VFA is modeled by means of a *voltage-controlled voltage source* (VCVS), with *a* representing the *open-loop gain*, in V/V, and *V _{d} *being the

*error signal*.

(*a*) (*b*)

**Figure 1. **Noninverting amplifier using the idealized model of (a) the VFA and (b) the CFA.

**Figure 1.**Noninverting amplifier using the idealized model of (a) the VFA and (b) the CFA.

By inspection,

*Equation (1)*

Using KVL and the voltage divider formula, we write

*Equation (2)*

where *b* is called the *feedback factor*, defined as

*Equation (3)*

Substituting Equation (2) into Equation (1), collecting, and solving for the ratio *V _{o}*/

*V*, we get

_{i}

*Equation (4)*

where *A* is called the *closed-loop gain*. Let us put the above expression in the more insightful form

*Equation (5)*

where

*Equation (6)*

and *T* is called the *loop gain*,

*Equation *(7)

This designation stems from the fact that *V _{d}* is first magnified by the open-loop gain

*a*and is then attenuated by the feedback factor

*b*, so the overall gain it experiences around the loop is

*T*=

*a*

*b*. (Note that

*T*is dimensionless.)

Clearly, the limit *T* → ∞ is achieved for *a* → ∞.

#### Example CFA: Current-Controlled Voltage Source

Turning next to Figure 1*b*, we observe that the CFA is modeled by means of a* current-controlled voltage source* (CCVS), with *z* representing the *open-loop gain*, in V/A or in W (for this reason, the CFA is also said to be a *transimpedance amplifier*.)

The *error signal* is now the current *I _{n}*

*out*of the

*unity-gain voltage buffer*connected across the input pins. (How the device manages to respond to this current will become clearer in the next article on current-feedback amplifiers, when we look at its transistor-level schematic.)

In the idealized representation shown, this buffer is assumed to have infinite input impedance and zero output impedance.

By inspection,

*Equation (8)*

Using KCL and Ohm’s law, and also exploiting the fact that the input buffer gives *V _{n}* =

*V*=

_{p}*V*, we write

_{i}

*Equation (9)*

where the *feedback factor* is now defined as

*Equation (10)*

and it is in A/V or Ω^{–1}. Substituting Equation (9) into Equation (8), collecting, and solving for the ratio *V _{o}*/

*V*, we get the

_{i}*closed-loop gain*

*Equation (11)*

Let us put this expression in the already familiar form of Equation (5):

*Equation (12)*

where

*Equation (13)*

and the *loop gain* is now

*Equation (14)*

This expression stems from the fact that *I _{n}* gets first multiplied by

*z*to produce

*V*, and then

_{o}*V*gets divided by

_{o}*R*to produce again a current, so the overall gain around the loop is

_{F}*T*=

*z*

*b*. (Note that

*z*is in V/A and

*b*is in A/V, so

*T*is dimensionless.) Clearly, the limit

*T*→ ∞ is achieved for

*z*→ ∞.

#### Comparing an Example CFA to an Example VFA

To better appreciate similarities and differences between the two op-amp types, consider the circuits of Figure 2, designed to amplify a 1.0 V input with *A _{ideal}* = 10.0 V/V.

For the VFA circuit, we use Equation (7) to find *T* = 10,000. Then we find *A* via Equation (5), and *V _{d}* via Equation (1).

(*a*) (*b*)

**Figure 2. **Configuring (a) a VFA and (b) a CFA for noninverting amplification with A_{ideal} = 10.0 V/V.

**Figure 2.**Configuring (a) a VFA and (b) a CFA for noninverting amplification with A

_{ideal}= 10.0 V/V.

For the CFA circuit, we use Equation (14) to find *T* = 400. Then we find *A* via Equation (12), and *I _{n}* via Equation (8). Moreover, we calculate the currents through

*R*and

_{G}*R*via Ohm’s law.

_{F}We make the following observations:

- The VFA needs a (small) control voltage
*V*to force the VCVS_{d}*aV*to sustain the given_{d}*V*. Only in the idealized limit of_{o}*a*→ ∞ do we get*V*→ 0, or_{d}*V*=_{n}*V*._{p} - The CFA has
*V*=_{n}*V*because of the unity-gain input buffer._{p} - The VFA draws zero current at both of its input pins.
- The CFA draws zero current at its noninverting input pin. However, the input buffer needs to source a (small) control current
*I*out of the inverting input pin to force the CCVS_{n}*zI*to sustain the given_{n}*V*. Only in the idealized limit of_{o}*z →*∞ do we get*I*→ 0._{n}

### AC Behavior of VFA and CFA Circuits

Most VFAs have an open-loop response a(jf) of the dominant-pole type depicted in Figure 3a, where a0 is the DC gain and fb is the dominant-pole frequency, also called the –3-dB frequency of |a(jf)|.

(*a*) (*b*)

**Figure 3. **Graphical visualization of the loop gain T as the difference between the open-loop gain curve and the 1/β curve for (a) the VFA circuit and (b) the CFA circuit of Figure 1.

**Figure 3.**Graphical visualization of the loop gain T as the difference between the open-loop gain curve and the 1/β curve for (a) the VFA circuit and (b) the CFA circuit of Figure 1.

This type of response is also said to exhibit a *constant gain-bandwidth product* (constant GBP), because at any point of the sloped portion of the curve the product GBP = |*a*|×*f* is constant. For instance, the popular 741 op-amp has *a*_{0} = 200,000 V/V and *f _{b}* = 5 Hz, so its GBP =

*a*

_{0}×

*f*= 1 MHz, and it remains constant all the way down the curve to the

_{b}*transition frequency*

*f*, so called because it marks the point at which the amplifier transitions from amplifying to attenuating.

_{t}Now, writing *T* = *a**b* = *a*/(1/*b*), taking the logarithms, and multiplying by 20 to convert to decibels, gives

*Equation (15)*

indicating that we can visualize the decibel plot of |*T*| as the *difference* between the decibel plots of |*a*| and |1/*b*|, as shown in Figure 3*a*. Note that at the crossover frequency *f _{x}* we have |

*T|*

_{dB}= 0, or |

*T|*= 1; moreover, |

*T|*> 1 for

*f*<

*f*, and |

_{x}*T|*< 1 for

*f*>

*f*. Because the GBP is constant, we can write (1+

_{x}*R*

_{2}/

*R*

_{1})×

*f*= 1×

_{x}*f*, or

_{t}

*Equation (16)*

Using Figure 3*a*, along with Equation (5), we construct the closed-loop ac response *A*(*jf*) as follows:

- At low frequencies, where |
*T|*>> 1, we approximate*A*(*jf*) ≅*A*._{ideal} - At high frequencies, where |
*T|*<< 1, we approximate*A*(*jf*) ≅*A*= (1+_{ideal}T*R*_{2}/*R*_{1})*a*(*jf*)*R*_{1}/(*R*_{1}+*R*_{2}) =*a*(*jf*). - The borderline frequency
*f*at which |_{x}*T*| = 1 approximates the –3-dB frequency of |*A*(*jf*)|.

The above procedure is shown in Figure 4*a* for three values of *A _{ideal}* (0, 20, and 40 dB, corresponding to 1, 10, and 100 V/V).

(*a*) (*b*)

**Figure 4. **Comparing the closed-loop gains of (a) the VFA and (b) the CFA noninverting amplifiers for three different values of A_{ideal} (0, 20, and 40 dB, corresponding to 1, 10, and 100 V/V).

**Figure 4.**Comparing the closed-loop gains of (a) the VFA and (b) the CFA noninverting amplifiers for three different values of A

_{ideal}(0, 20, and 40 dB, corresponding to 1, 10, and 100 V/V).

Note that as we increase *A _{ideal}* by raising the

*R*

_{2}/

*R*

_{1}ratio, the –3-dB frequency decreases in proportion, by Equation (16), so the VFA circuit is said to exhibit a

*gain-bandwidth tradeoff*.

Turning next to the CFA case of Figure 3*b*, we observe that the open-loop response *z*(*jf*) of a CFA is also of the *dominant-pole* type, with *z*_{0} as the *dc gain* and *f _{b}* as the

*dominant-pole frequency*. Since

*z*is in V/A or W, we can no longer express it in decibels; however, we still use logarithmic scales, after which Equation (14) indicates that we can visualize |

*T*| as the

*difference*between the logarithmic plots of |

*z*| and |1/

*b*|, as depicted in Figure 3

*b*.

We now see an inherent advantage of the CFA: Since its crossover frequency *f _{t}* depends

*only*on

*R*(rather than on 1 +

_{F}*R*/

_{F}*R*), we can keep

_{G}*R*

_{F}*fixed*and establish different values of

*A*by

_{ideal}*varying*

*R*. As illustrated in Figure 4

_{G}*b*, all closed-loop responses now exhibit the

*same*–3-dB frequency.

### Summary

We can summarize our comparison of voltage-feedback amplifiers and current-feedback amplifiers via two additional bullets:

- The VFA noninverting amplifier is constrained by a
*gain-bandwidth tradeoff*. - The CFA noninverting amplifier is relatively free from a gain-bandwidth tradeoff, since its closed-loop gain can be set independently of frequency via
*R*._{G}

An additional advantage of CFAs compared to VFAs is the *absence of slew-rate limiting*, a feature that will be investigated in the next article, along with real-life departures from the idealized model of Figure 1*b*.

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