All About Circuits

Network Analysis Techniques

Superposition Theorem


17 questions By Tony R. Kuphaldt

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  • Question 7 of 17

    Note that this circuit is impossible to reduce by regular series-parallel analysis:





    However, the Superposition Theorem makes it almost trivial to calculate all the voltage drops and currents:





    Explain the procedure for applying the Superposition Theorem to this circuit.

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  • Question 8 of 17

    Use the Superposition Theorem to calculate the amount of current going through the 55 Ω heater element. Ignore all wire and connection resistances, only considering the resistance of each fuse in addition to the heater element resistance:




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  • Question 9 of 17

    Suppose a DC generator is powering an electric motor, which we model as a 100 Ω resistor:





    Calculate the amount of current this generator will supply to the motor and the voltage measured across the motor’s terminals, taking into account all the resistances shown (generator internal resistance rgen, wiring resistances Rwire, and the motor’s equivalent resistance).

    Now suppose we connect an identical generator in parallel with the first, using connecting wire so short that we may safely discount its additional resistance:





    Use the Superposition Theorem to re-calculate the motor current and motor terminal voltage, commenting on how these figures compare with the first calculation (using only one generator).

    Reveal answer
  • K
    KC Anoruo July 28, 2020

    As a student, it will be better if these worksheets had not only answers but explanations as well so one can see where they went wrong.
    Thank you.

    Like. Reply
    • ituo October 28, 2020
      i really don't know how 44v 0.15Ω could produce like 3.992 A so small current may be i really should leard SPICE or give up not like you have teacher to ask
      Like. Reply
      • RK37 October 29, 2020
        If you're having difficulty understanding one of these exercises, you could try posting a question in the AAC forum: https://www.allaboutcircuits.com/forums/
        Like. Reply