All About Circuits

Parallel Wire Inductance Calculator


This tool is designed to calculate the inductance of two parallel wires


Inputs

 
 
 

Outputs

H

Overview

Inductance is the measure of how the magnetic flux and the current that created it, are linked. Any material that has current flowing through it and produces a magnetic flux has inductance. This tool calculates the inductance of a common object in electrical engineering: two parallel wires.

To use this tool, just fill in the required fields and click on the "calculate" button. Note: Copper, which most wires are made of, have a relative permeability approximately equal to 1. 

Equation

$$L_{wires}\approx \frac{\mu _{o}\mu _{r}L}{\pi}\cosh^{-1}\left ( \frac{S}{D} \right )$$

Where:

$$S$$ = spacing between conductors (m)

$$D$$ = conductor diameter (m)

$$L$$ = length of conductor (m)

Applications

Inductance is an important parameter that needs to be determined, especially in radio communications technology. Impedance (the measure of opposition to alternating current) of materials is a function of frequency, and for inductive materials, an increase in frequency means an increase of impedance. Knowing the inductance of materials means knowing their effects on the applied signal. When paired with stray capacitance at the right conditions, inductance can also result in resonance. This could result in an unwanted filter that could impede the signals propagating through a device. 

Further Reading

  • tonigau April 20, 2020

    This calc would be very handy, but may need some further work…
    1.  trying to calc 16mm2 sq copper cable(2 core)
    Distance = 5000mm, distance apart=3mm, entering diameter greater than 3mm gives NaN, dia=3 gives 0.00
    2. The polarity of the current in each wire is not specified. Is it a 2 core cable (+ & -) source to load, or 2 parallel wires to increase current (both current same direction)?
    3. The calc. page doesn’t have a rev No. or Date.
    4. The output could have selector for mH, uH ...

    If I knew how to contribute I would try to improve.

    Like. Reply
    • S
      salty_solution January 10, 2025
      For 1: You can see from the diagram: S measures to the center of each wire, so it must be greater than the diameter or else the physical separation would be zero. That's why you get 0 or NaN for smaller S. The "spacing between conductors" description is definitely misleading. For 2: The parallel wires scenario described here is the same current running in opposite directions. If they were parallel wires in the same direction the formula would just be kirchoff's law (1/(1/L1 + 1/L2)). And if they were unrelated, we would only be concerned with mutual inductance and self inductance independently. Funny that there's no mutual inductance calculator. I've run into both of these points of confusion myself, so I agree the page could spell things out better.
      Like. Reply
  • S
    salty_solution February 04, 2025

    When I use the formula in the Grange reference, I get a very different result:

    ‘L = μ0 L/π·[ ln(2S/D) + 1/4 ]

    For a wire with diameter 4.11 mm, separation of 8.22mm and length of 182.88 cm, I get 1.19 muH from this formula, but the AAC formula only computes 0.96 muH.  How is the formula used on this webpage derived? Are there any texts that explain it?  Are there constraints for its accuracy?

    Like. Reply