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Algebraic Equation Manipulation for Electric Circuits
19 questions By Tony R. Kuphaldt
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Question 13 of 19
Solve for the value of x in the following equations:
5x = 15 x = 6 = x 2x = Reveal answer5x = 15 x = 3 6 = x 2x = 12 Notes:Have your students come to the front of the class and show everyone else the techniques they used to solve for the value of x in each equation. Remind them to document each and every step in the process, so that nothing is left to guess or to chance.
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Question 14 of 19
Solve for the value of a in the following equations:
Equation 1: a − 4 = 10
Equation 2: 30 = a + 3
Equation 3: −2a = 9
Equation 4: a/4 = 3.5
Reveal answerEquation 1: a = 14
Equation 2: a = 27
Equation 3: a = −4.5
Equation 4: a = 14
Notes:Have your students come to the front of the class and show everyone else the techniques they used to solve for the value of a in each equation. Remind them to document each and every step in the process, so that nothing is left to guess or to chance.
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Question 15 of 19
Solve for the value of x in the following equations:
$$\frac {x+5}{2} = 20 \ \ \ \ \ \ \ \ \ \ \ x =$$
$$6 = \sqrt{x-2} \ \ \ \ \ \ \ \ \ \ \ x =$$
Reveal answer$$\frac {x+5}{2} = 20 \ \ \ \ \ \ \ \ \ \ \ x =35$$
$$6 = \sqrt{x-2} \ \ \ \ \ \ \ \ \ \ \ x =38$$
Notes:Have your students come to the front of the class and show everyone else the techniques they used to solve for the value of x in each equation. Remind them to document each and every step in the process, so that nothing is left to guess or to chance.
Question 14, Equation 2 - the ‘+’ symbol is missing between ‘a 3’.
Question 17, right-hand equation - the square-root should only be over the left side of the equation.
Question 19, Hint - the ‘+’ symbol is missing between ‘I 0.005’.
They do seem to be correct in the equivalent questions in the PDF version though.
In the answer to question 8, the second solution has R1 on the right side of the equation when it should be R.