Circuit Design with Limited Gate Inputs

In any practical design of logic circuits, the maximum inputs a gate (fan-in) can have is limited. This number can vary from two, three, four, eight, or some other number, depending on the type of gate being used in designing a circuit. If any two-level realization of a circuit demands more gate inputs than permitted, the logic expression can be factored to obtain a multi-level realization. Below is an example that asks to realize $$f(a, b, c, d) = \sum m(0, 3, 4, 5, 8, 9, 10, 14, 15)$$ by using three-input NOR gates.

This expression is a two-level realization; however, it requires two four-input and one five-input gate. This requirement is not an ideal way to design any functional combinational circuit. In order to reduce this expression, f’ is factored to reduce the maximum number of gate inputs. After factoring this logic expression, the number of gate inputs can be reduced to three, as shown below.

When designing a large output circuit with more than two levels, the best technique would be to minimize each function separately. In order to increase the number of levels, the two-level logic expressions must be factored. When factoring, introducing common terms wherever possible is the most ideal way to go about simplification. Below is another example that asks to realize the logic functions by using ONLY two-input NAND gates and inverters. Having minimized each logic function individually, one would find:

This result shows that each logic function requires one three-input OR gate. In order to use the OR gate on each function, reduction of gate inputs by factoring is completed below.

Looking closely, the logic expression *f*_{2} has a common term with *f*_{1 }of * a'b*, so by using the second expression of

*f*the last three-input gate from

_{2},*f*

_{3}can be eliminated as shown below:

The resulting logic circuit, having used common terms *a'b* and *a *+ *c'*, has OR gates at each output. Converting to NAND gates is straightforward, as shown on the right side of the figure.

### Delays in Gates and Timing Diagrams

If the input of a logic gate is changed, the output will not change instantaneously. The reason behind this is elements that switch the inputs within the gate take a fixed time to react to change, so the resulting change output is delayed with respect to the input. The propagation delay in an inverter figure shown below any possible waveforms of input and output for an inverter. For a change in output delayed by time, $$ \varepsilon$$, taken respectfully to the input, is said to have a propagation delay of $$ \varepsilon$$. A propagation delay for a 0 to 1 output change may be different than that of a delay for a 1 to 0 change. Some propagation delays can be neglected if they are as short as a few nanoseconds. However, it is good practice to analyze these sequential circuits, no matter how short the delay may be.

More than likely, a timing diagram will be used to analyze sequential circuits. Timing diagrams can be used to show different signals in a circuit as a function of time. When plotting numerous variables, they are plotted along the same time scale so the times at which these variables change with respect to each other can be easily understood.

For a circuit with two gates, as shown below, each gate is assumed to have propagation delay of 20 ns. The diagram specifies what will happen if gate inputs B and C are held at regular values of 1 and 0, respectively, and gate input A is changed to 1 at t = 40 ns where it is then changed back to 0 at t = 100 ns. The gate output of G_{1} changes exactly 20 ns after A changes, and finally the gate output of G_{2} changes exactly 20 ns after G_{1} changes.

The figure below depicts a timing diagram for a logic circuit with a delay element. Input X consists of two pulses: the first pulse is 2 microseconds wide and the second pulse is 3 microseconds wide. The delay element that tangents off of X has output Y, which is identical to the input, X, but it is delayed by 1 microsecond. What this means is that Y changes from a value of 1, 1 microsecond after the rising edge of the X pulse and then returns to a value of 0, 1 microsecond after the falling edge of the X pulse. Z, which is the output of this AND gate, should always be 1 during the time interval for which both X and Y have a value of 1. Assuming that there is a small propagation delay in the AND gate of $$ \varepsilon$$, then the output, Z, will provide the following timing diagram:

### Coming Up

At this point, you should have an understanding of how to draw a timing diagram for any combinational circuit with and without gate delays, an understanding of designing and simplifying two or multiple level logic circuits, as well as a full grasp on how time delays affect gate operations. A further topic that will be explored is hazards in combinational logic circuits, specifically finding static 0- and 1-hazards.

1 CommentLoginp.cee.b2016-01-29Great article and so well illustrated. May I ask what tool you used to draw the diagrams and the circuits?