Mathematics for Electronics
Algebraic Substitution for Electric Circuits
13 questions By Tony R. Kuphaldt
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Question 7 of 13
We know that the voltage in a parallel circuit may be calculated with this formula:
$$E = I_{total} \ R_{total}$$
We also know that the current through any single resistor in a parallel circuit may be calculated with this formula:
$$I_R = \frac {E}{R}$$
Combine these two formulae into one, in such a way that the E variable is eliminated, leaving only IR expressed in terms of Itotal, Rtotal, and R.
Reveal answer$$I_R = I_{total} (\frac{R_{total}}{R})$$
How is this formula similar, and how is it different, from the “voltage divider” formula?
Notes:Though this “current divider formula” may be found in any number of electronics reference books, your students need to understand how to algebraically manipulate the given formulae to arrive at this one.
At first it may seem as though the two divider formulae (voltage versus current) are easy to confuse. Is it \(\frac {R}{R_{total}}\) or \(\frac {R_{total}}{R}\) ? However, there is a very simple way to remember which fraction belongs with which formula, based on the numerical value of that fraction. Mention this to your students and at least one of them will be sure to recognize the pattern.
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Question 8 of 13
Suppose we only knew the emitter and base currents for an operating transistor and wished to calculate β from that information. We would need a definition of beta cast in terms of IE and IB instead of IC and IB.
Apply algebraic substitution to the formula \(\beta = \frac {I_C}{I_B}\) so that beta (β) is defined in terms of IE and IB. You may find the following equation helpful in your work:
$$I_E = I_C + I_B$$
Reveal answer$$\beta = \frac {I_E}{I_B} - 1$$
Notes:This question is nothing more than an exercise in algebraic manipulation.
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Question 9 of 13
The resistance of a piece of copper wire at temperature T (in degrees Celsius) is given by the following formula:
$$R_T = R_o \ [1 + 0.004041(T − 20)]$$
Suppose you wished to alter this formula so it could accept values for T in units of degrees Fahrenheit instead of degrees Celsius. Suppose also that the only formula you are able to find for converting between Fahrenheit (TF) and Celsius (TC) is this one:
$$T_F = T_C (\frac{9}{5})+ 32$$
Combine these two formulae into one solving for the resistance of a copper wire sample (RT) at a specific temperature in degrees Fahrenheit (TF), given the specimen’s “reference” resistance (Ro) at 20o Celsius (room temperature).
Reveal answer$$R_T = R_o \ [1 + 0.004041(\frac{5}{9}T_F - 37.\overline{77})]$$
Notes:Solving this algebraic problem requires both manipulation of the temperature equation and substitution of variables. One important detail I incorporated into this question is the lack of a subscript for T in the original resistance formula. In the first sentence I identify that temperature as being in degrees Celsius, but since there is no other T variables in the equation, I did not have to include a “C” subscript. When students look to the Celsius-Fahrenheit conversion formula to substitute into the resistance formula, they must decide which T in the conversion formula to use, TF or TC. Here, I purposely wrote the conversion formula in terms of TF to see how many students would blindly substitute TF for T in the resistance formula instead of properly identifying TC as the variable to substitute and doing the work of manipulation.
Far from being a “trick” question, this scenario is very realistic. Formulae found in reference manuals do not necessarily use standardized variables, but rather cast their variables according to context. Multiple formulae will most likely not be written with identical subscripted variables just waiting to be substituted. It is the domain of the intelligent technician, engineer, or scientist to figure out what variables are appropriate to substitute based on context!
In a lot of question, the ‘+’ symbol is not printed. Can you please correct this as it causes confusion while trying to solve the equation?
Question 9 says “Combined these two formulae into one solving for the resistance of a copper wire sample (RT) at a specific temperature in degrees Celsius (TC)...”.
I think it should be “at a specific temperature in degrees Fahrenheit (TF)”.