Mathematics for Electronics
Algebraic Substitution for Electric Circuits
13 questions By Tony R. Kuphaldt
-
Question 10 of 13
A bipolar junction transistor parameter similar to β is älpha,” symbolized by the Greek letter α. It is defined as the ratio between collector current and emitter current:
$$a = \frac{I_C}{I_E}$$
Apply algebraic substitution to this formula so that alpha is defined as a function of beta: α = f(β). In other words, substitute and manipulate this equation until you have alpha by itself on one side and no variable except beta on the other.
You may find the following equations helpful in your work:
$$\beta = \frac{I_C}{I_B} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ I_E=I_C+I_B$$
Reveal answer$$a = \frac{\beta}{\beta + 1}$$
Follow-up question: what range of values might you expect for α, with a typical transistor?
Notes:This question is nothing more than an exercise in algebraic manipulation.
-
Question 11 of 13
The Q, or quality factor, of an inductor circuit is defined by the following equation, where Xs is the series inductive reactance and Rs is the series resistance:
$$Q = \frac{X_s}{R_s}$$
We also know that we may convert between series and parallel equivalent AC networks with the following conversion equations:
$$R_s R_p = Z^2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ X_sX_p = Z^2$$

Series and parallel LR networks, if truly equivalent, should share the same Q factor as well as sharing the same impedance. Develop an equation that solves for the Q factor of a parallel LR circuit.
Reveal answer$$Q = \frac{R_p}{X_p}$$
Follow-up question: what condition gives the greatest value for Q, a low parallel resistance or a high parallel resistance? Contrast this against the effects of low versus high resistance in a series LR circuit, and explain both scenarios.
Notes:This is primarily an exercise in algebraic substitution, but it also challenges students to think deeply about the nature of Q and what it means, especially in the follow-up question.
-
Question 12 of 13
The equation relating probability of continued performance for a component or a system versus time may be expressed as follows:
x = e−t / m Where,
x = Probability (a number between 0 and 1, inclusive)
e = Euler’s constant ( ≈ 2.7182818)
t = Time of continuous operation
m = Mean Time Between Failure of the component or system
The unit of time for both t and m must be the same. That is, if t is measured in years, then m must also be expressed in years or else the equation will give very misleading answers.
Suppose, though, we were given m in years, and the operating time t in days. Substitute the relationship td = 365 ty into the reliability equation so that we will have a new equation that can take t in days (td) and m in years, and still provide the correct answer.
Reveal answerx = e−td / 365 m Notes:This is really nothing more than a simple exercise in mathematical substitution.
The equation came from the Standard Handbook of Engineering Calculations by Tyler G Hicks, P.E. (1972), page 5-21.

In a lot of question, the ‘+’ symbol is not printed. Can you please correct this as it causes confusion while trying to solve the equation?
Question 9 says “Combined these two formulae into one solving for the resistance of a copper wire sample (RT) at a specific temperature in degrees Celsius (TC)...”.
I think it should be “at a specific temperature in degrees Fahrenheit (TF)”.