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Discrete Semiconductor Devices and Circuits

Bipolar Junction Transistor (BJT) theory


28 questions By Tony R. Kuphaldt

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  • Question 22 of 28

    Draw the polarities ( and -) of the applied voltages necessary to turn both these transistors on:





    Also, draw the direction of the controlled current (flowing between collector and emitter) that will result from a power source properly connected between these terminals.

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  • Question 23 of 28

    Students new to the study of transistors often have difficulty remembering the proper directions of currents through bipolar junction transistors, since there are three different currents (IB, IC, IE) and they must “mesh” through the transistor in a particular way.

    Draw the proper current directions for each of these transistors, and explain how you are able to remember the correct directions they go:




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  • Question 24 of 28

    Predict how all three transistor currents (IB, IC, and IE) will be affected as a result of the following faults. Consider each fault independently (i.e. one at a time, no multiple faults):





    Base resistor RB fails open:
    Collector resistor RC fails open:
    Solder bridge (short) past base resistor RB:
    Solder bridge (short) past collector resistor RC:

    For each of these conditions, explain why the resulting effects will occur.

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  • LvW November 15, 2019

    What surprises me is the following: I did not see any mentioning of the most important BJT parameter: Transconductance gm.
    (Instead, you are stating that the beta-value would be a very important parameter - which is NOT the case!).
    Like some other low-level electronic books and papers you treat the BJT as a cittent-controlled device - this is simply wrong.
    There is not a single proof that the BJT would be a CCCS !
    However, there are many theoretical explanations, measurements and observable facts which clearly show that the BJT is - of course - voltage-controlled. Who can deny it ? With which arguments? Ic=beta x Ib is just a formula - a misinterpretation of Ib=Ic/beta.

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