All About Circuits

Network Analysis Techniques

Thevenin’s, Norton’s, and Maximum Power Transfer Theorems


46 questions By Tony R. Kuphaldt

Page 7 of 16 0 of 46 answers revealed (0%)
  • Question 19 of 46

    Give a step-by-step procedure for reducing this circuit to a Thévenin equivalent circuit (one voltage source in series with one resistor):




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  • Question 20 of 46

    Suppose you were handed a black box with two metal terminals on one side, for attaching electrical (wire) connections. Inside this box, you were told, was a current source connected in parallel with a resistance.





    Your task was to experimentally determine the values of the current source and the resistor inside the box, and you did just that. From your experimental data you then sketched a circuit with the following component values:





    However, you later discovered that you had been tricked. Instead of containing a current source and a resistor, the circuit inside the box was actually a voltage source connected in series with a resistor:





    Demonstrate that these two different circuits are indistinguishable from the perspective of the two metal terminals, and explain what general principle this equivalence represents.

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  • Question 21 of 46

    An AC voltage source with an internal (“Thévenin”) resistance of 50 Ω is connected to a step-down transformer with a winding ratio of 10:1. What is the equivalent source voltage and resistance, as seen from the load terminals?




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  • texhnolyzze January 01, 2024

    I think there is an error in 8th question, Thevenin’s resistance must be 479.53 and not 210.53

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    • D
      dalewilson January 04, 2024
      You are correct, or we both made the same error. :) I have updated the answer to reflect the correct value. Thanks for being a loyal All About Circuits reader and helping us create the best possible content!
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  • texhnolyzze January 06, 2024

    There is another mistake in question 39:

    “this student’s power source circuit resembles a 3 volt source in series with a 5 kΩ resistance”—should be 2.5 kΩ resistance

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