DC Electric Circuits
Kirchhoff’s Laws
48 questions By Tony R. Kuphaldt
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Question 34 of 48
Calculate the total current output to the load resistor by this set of parallel-connected current sources:

Also, calculate the voltage dropped across Rload.
Reveal answerThe total current in this circuit is 27 mA, and the load voltage is 40.5 volts.
Follow-up question: trace the direction of current through all three sources as well as the load resistor. Compare these directions with the polarity of their shared voltage. Explain how the relationship between voltage polarity and current direction relates to each component’s identity as either a source or a load.
Notes:Have your students collectively agree on a procedure they may use to accurate discern series voltage sums and polarities. Guide their discussion, helping them identify principles that are true and valid for all series circuits.
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Question 35 of 48
Calculate the total current output to the load resistor by this set of parallel-connected current sources:

Also, calculate the voltage dropped across Rload.
Reveal answerThe total current in this circuit is 4 mA, and the load voltage is 18.8 volts.
Follow-up question: indicate the polarity of the voltage across the load resistor with “ ” and “-” symbols.
Notes:Have your students collectively agree on a procedure they may use to accurate discern series voltage sums and polarities. Guide their discussion, helping them identify principles that are true and valid for all series circuits.
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Question 36 of 48
Use Kirchhoff’s Current Law to calculate the magnitude and direction of the current through resistor R4 in this resistor network:

Reveal answer
Notes:It is not necessary to know anything about series-parallel or even parallel circuits in order to solve the R4‘s current - all one needs to know is how to use Kirchhoff’s Current Law.




I think there is a mistake in question 28 more specifically step 3 and 4. I think their answers are switched. Step 3 should be 12 and Step 4 should be -24
In the notes for question 4, the diagram should have a 47k resistor, not 4.7k.